Here are some questions (on amplitude modulation) of the type you are most likely to encounter in your entrance exam:

**(1) A carrier wave of peak value 16 V is used to transmit a note of frequency 1000 Hz. What should be the peak value of the modulating signal to have a modulation index of 60% using amplitude modulation? **

**(a) 12 V**

**(b) 11.2 V**

**(c) 10.4 V**

**(d) 9.6 V**

**(e) 7.2 V **

This question demands from you merely a basic knowledge of the modulation process and you are expected to calculate the modulation index (μ) using the equation,

*μ* = *A*_{m}/*A*_{c} where *A*_{m} and *A*_{c} are the amplitudes of the modulating signal and the carrier respectively.

Therefore, 0.6 = *A*_{m}/16, from which* A*_{m} = 9.6 V. (The frequency of the modulating signal is just a distraction in this question).

[In a practical modulator, the modulating signal amplitude may not be *μ* times the carrier amplitude. For instance, if the carrier is applied on the base side and the modulating signal is applied on the collector side of a transistor, the carrier amplitude (at the base) will be much less than the modulating signal amplitude, even though the modulation index is less than 100%. Of course, the carrier will appear in the amplified form at the collector. The modulation index (*μ)* in all situations will be correctly obtained if you consider it as the *ratio of the* *amplitude of variation of the envelope* of the amplitude modulated carrier *to the amplitude of the unmodulated carrier*. But problems with the above type of statement are often seen].

**(2) The maximum amplitude of an amplitude modulated wave is 12 V and the minimum amplitude is 4V. The modulation percentage is **

**(a) 20**

**(b) 30**

**(c) 50**

**(d) 60**

**(e) 80 **

The modulation percentage is the modulation index expressed as percentage.

The *maximum* amplitude of an amplitude modulated (AM) wave is the *sum* of the amplitude of the unmodulated carrier and the amplitude of variation of the envelope of the AM wave.

The *minimum* amplitude of an AM wave is the *difference* between the amplitude (*A*_{c}) of the unmodulated carrier and the amplitude (*A*_{m}) of variation of the envelope of the AM wave.

Therefore, we have* *(*A*_{c} + *A*_{m}) = 12 V

(*A*_{c} – *A*_{m}) = 4 V

From these equations, *A*_{c} = 8 V and *A*_{m} = 4 V so that

*μ* = *A*_{m}/*A*_{c} = 4/8 = 0.5 = 50%

**(3) An unmodulated carrier has a peak value of V volt. When it is amplitude modulated with a sine wave, the maximum peak to peak value (of the modulated carrier) is 3 V volt. The modulation index is**

**(a) 0.33**

**(b) 0.5**

**(c) 0.6**

**(d) 0.66**

**(e) 0.8 **

The *maximum* *peak value* (maximum amplitude) of the modulated carrier is 3*V*/2 volt.

Therefore, (*A*_{c} + *A*_{m}) = 3*V*/2

Since the amplitude of the unmodulated carrier (*A*_{c}) is *V* volt, the amplitude (*A*_{m}) of the variation of the envelope of the modulated carrier is *V*/2. Therefore, The modulation index is given by

*μ* = *A*_{m}/*A*_{c} = (*V*/2)/*V* = 0.5

**(4) An amplitude modulated wave has modulation index 0.6. If the power carried by the carrier component in the modulated wave is P _{c }, what is the power carried by the upper and lower side bands (together)?**

**(a) 0.6 P _{c}**

**(b) 0.54 P _{c} **

**(c) 0.36 P _{c} **

**(d) 0.46 P _{c} **

**(e) 0.18 P _{c} **

The total power (P) carried by an amplitude modulated wave is given by

P = P_{c}[1+* *(*μ ^{2}/*2) where P

_{c}is the carrier power and

*μ*is the modulation index.

Therefore, the power carried by the two side bands together is

P_{c }×*μ ^{2}/*2 = P

_{c}×(0.6)

^{2}/2 = 0.18 P

_{c}.

[This shows how much power is wasted in the carrier component which does not carry any information. Further, we need only one side band to extract the modulating signal. This points to the benefit of the suppressed carrier single side band transmission].

**(5) An AM radio station using double side band transmitted carrier system employs a carrier of frequency 1.2 MHz. If the modulating signal frequency is 2 kHz, the frequencies present in the modulated carrier are**

**(a) 1.2 MHz and 1.4 MHz**

**(b) 1 MHz, 1.2 MHz and 1.4 MHz**

**(c) 1.198 MHz, 1.2 MHz and 1.202 MHz**

**(d) 1.198 MHz and 1.202 MHz **

**(e) 1.2 MHz and 1.202 MHz**

The double side band transmitted carrier system** **is the one employed by ordinary broadcast stations. The amplitude modulated wave will contain the carrier frequency (f_{c}) as well as the upper and lower side frequencies f_{c} + f_{m} and f_{c} – f_{m}. Therefore, the correct option is (c).

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