Friday, November 24, 2017

JEE Main 2018 Online Application Process to Start on 1st December 2017



Joint Entrance Examination (Main) 2018 [JEE Main 2018] will be conducted on April 8, 2018 (Sunday) (Pen & Paper Based Examination) and on April 15, 2018 (Sunday) & April 16, 2018 (Monday) (Computer Based Examination).

Candidates of JEE Main have to apply online only through JEE (Main) website www.jeemain.nic.in.

The online application process will start on 1st December, 2017. The last date for application is 1st January, 2018 and fee can be paid upto 2nd January 2018.

CBSE has decided to make use of Aadhar to ascertain the accuracy of details and the identity of the candidates (in the case of those who are entitled to obtain Aadhar).
Visit the JEE Main website www.jeemain.nic.in for complete information.

Friday, February 03, 2017

Apply for KEAM 2017



The Commissioner for Entrance Examinations (Govt. of Kerala) has invited applications for the Entrance Examinations for admission to Professional Degree Courses in the State for the year 2016-17. Candidate can apply online on the website of the Commissioner for Entrance Examinations during the period from 1st February 2017 to 27th February 2017.
The courses offered are:
(a) Medical Courses:
(i) M.B.B.S. (ii) B.D.S. (iii) B.H.M.S. (Homoeo) (iv) B.A.M.S. (Ayurveda) (v) B.S.M.S. (Sidha) (vi) B.U.M.S. (Unani)
(b) Allied Courses:
(i) B.Sc. (Hons.) Agriculture (ii) B.Sc. (Hons.) Forestry
(iii) Veterinary: B.V.Sc. & A.H. (iv) Fisheries: B.F.Sc.
(c) Engineering Courses:
B.Tech. [including B.Tech. (Agri. Engg.) & B.Tech. (Food Engg.) courses under the Kerala Agricultural University, B.Tech. (Dairy Technology) & B.Tech. (Food Technology) courses under the Kerala Veterinary & Animal Sciences University], B.Tech. (Food Science & Technology) Course under Kerala University of Fisheries & Ocean Studies
(d) Architecture Course:
B.Arch. (No Entrance Examination. Admission is based on merit as assessed by equal weightage to NATA Score and marks/grades in the Qualifying Examination)

Note that candidates satisfying the eligibility conditions as laid down in the Prospectus and who seek admission to any or all of the above mentioned courses have to apply online through the website of the Commissioner for Entrance Examinations, 
www.cee.kerala.gov.in from 1st February 2017 to 27th February 2017 and should send the printout of the online submitted application along with supporting documents to the Commissioner for Entrance Examinations on or before the last date and time.
The CEE will conduct Entrance Examination for admission to Engineering Courses only.
The CEE will not conduct any Entrance Examination for admission to B.Arch. course and Medical & Allied courses. However, candidates seeking admission to B.Arch. course
should compulsorily appear and qualify the National Aptitude Test in Architecture (NATA) conducted by the Council of Architecture (COA) on or before 10.06.2017. Candidates seeking admission to any of the Medical & Allied courses should compulsorily appear and qualify the National Eligibility-cum-Entrance Test-Under Graduate (NEET-UG) 2017 conducted by the Central Board of Secondary Education (CBSE)

The entrance examinations for Engineering Courses except Architecture will be conducted on 24th and 25th April 2017.
For details you may visit the official website of the commissioner, http://www.cee-kerala.org

Apply For National Eligibility cum Entrance Test (UG) – 2017 [NEET(UG)-2017]



National Eligibility cum Entrance Test (UG) – 2017 [NEET(UG)-2017] will be conducted on Sunday, the 7th May, 2017 by the Central Board of Secondary Education (CBSE). 
This test is conducted for admission to MBBS/BDS Courses in India in Medical/Dental Colleges run with the approval of Medical Council of India/Dental Council of India under the Union Ministry of Health and Family Welfare, Government of India, except for the institutions established through an Act of Parliament e.g. AIIMS and JIPMER Puducherry. 
Complete details of NEET 2017 (UG) can be obtained from the website http://cbseneet.nic.in

Tuesday, December 27, 2016

NEET 2016 Questions on Electric Circuits




“The release of atomic energy has not created a new problem. It has merely made more urgent the necessity of solving an existing one.”


Albert Einstein

Questions (1) and (2) given below were asked in the National Eligibility cum Entrance Test (NEET) conducted in July 2016. Question (3) is a modification of question (2).
Here are the questions with their solution:
(1) A filament bulb (500 W, 100 V) is to be used in a 230 V main supply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500 W. The value of R is :
(1) 26 Ω
(2) 13 Ω
(3) 230 Ω
(4) 46 Ω



The resistance Rf of the filament lamp related to its power P and voltage V as
            Rf = V2/P = 1002/500 = 20 Ω
The current through the filament lamp is P/V = 500/100 = 5 A        
Since the main supply voltage is 230 volt and the total resistance in the series circuit is (20 + R) ohm, we have
            230 volt/(20 + R) ohm = 5 ampere
Therefore (20 + R) = 46 from which R = 26 Ω


(2) The potential difference (VA – VB) between the points A and B in the given figure is
(1) + 6 V
(2) + 9 V
(3) – 3 V
(4) + 3 V
The voltage across 2 Ω resistor due to the current of 2A  in it is 4 V. Similarly the voltage across 1 Ω resistor is 2 V. These voltages and the battery voltage of 3 V are in conjunction and hence they add up. The potential difference (VA – VB) between the points A and B is therefore equal to (4V + 3 V + 2 V) = 9 V.


(3) If the battery voltage in question no.(2) is reversed as shown in the adjacent figure, the potential difference (VA – VB) between the points A and B will be
(1) + 12 V
(2) + 9 V
(3) – 6 V
(4) + 3 V
In this case the voltages across the 2 Ω resistor and the 1 Ω resistor are in conjunction while the battery voltage is in opposition. Therefore, the potential difference (VA – VB) between the points A and B is equal to (4V 3 V + 2 V) = 3 V.