tag:blogger.com,1999:blog-32436271.post9030531558552444072..comments2023-03-30T19:46:46.914+05:30Comments on Physicsplus: Kerala Engineering Entrance 2009 Questions (MCQ) on Alternating Current CircuitsUnknownnoreply@blogger.comBlogger4125tag:blogger.com,1999:blog-32436271.post-19148265847629053442018-03-21T22:56:53.110+05:302018-03-21T22:56:53.110+05:30Thankyou,Sir.Thankyou,Sir.Anonymoushttps://www.blogger.com/profile/07097478831389474267noreply@blogger.comtag:blogger.com,1999:blog-32436271.post-53614434909290058322018-03-21T19:47:24.061+05:302018-03-21T19:47:24.061+05:30If the area vector (which is perpendicular to the ...If the area vector (which is perpendicular to the plane of the coil, by convention) makes an angle θ with the magnetic field vector, the magnetic flux (φ) linked with the coil is AB cos θ for a single turn coil and is NABcos θ for a coil of N turns. Here θ is the angle turned by the coil in time t so that θ = ωt where ω is the angular velocity of rotation of the coil. Therefore φ = NABcos ωt <br /> Since the induced emf is –dφ/dt, the instantaneous value of induced emf is NABω sin ωt <br />The maximum value of the induced emf is therefore NABω<br />MVhttps://www.blogger.com/profile/05910408858112321196noreply@blogger.comtag:blogger.com,1999:blog-32436271.post-37374563207659297482018-03-20T14:01:54.412+05:302018-03-20T14:01:54.412+05:30Question 4 under Kerala Engineering Entrance 2009 ...Question 4 under Kerala Engineering Entrance 2009 Questions (MCQ) on Alternating Current Circuits<br />Where can i find the derivation for induced emf=NABwAnonymoushttps://www.blogger.com/profile/07097478831389474267noreply@blogger.comtag:blogger.com,1999:blog-32436271.post-27937114668237415782009-07-29T09:52:46.830+05:302009-07-29T09:52:46.830+05:30Heavy computation!Heavy computation!control valveshttp://www.meaincorporated.com/noreply@blogger.com